Program:
enter the year
read y
a=`expr $y % 4`
b=`expr $y % 100`
c=`expr $y % 400`
if [ $a -eq 0 -a $b -ne 0 -o $c -eq 0 ]
then
echo $y is leap year
else
echo $y is not leap year
fi
Input/OutPut
2010
2010 is not leap year
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This comment has been removed by the author.
ReplyDeletedaysinyear=`cal | grep -v $ | grep -v [a-z] | wc -w`
ReplyDeleteif daysinyear = 366 then leapyear
thanks Great work
ReplyDelete#!/bin/bash
ReplyDeleteecho "Please Enter a year"
read year
echo Entered year is : $year
d=`expr $year % 4`
if [ $d -eq 0 ]
then echo "$year is a leap year"
else echo "$year is not a leap year"
fi
This comment has been removed by the author.
ReplyDeleteGreat Job Sir
ReplyDeleteIs it working?
ReplyDelete